How Do Charges Affect Net Force Calculation?

AI Thread Summary
The discussion focuses on calculating the net force exerted on a charge (q1) by two other charges (q2 and q3) with different magnitudes and signs. The user attempts to compute the forces using Coulomb's law and breaks them into components, seeking validation of their calculations. However, another participant suggests a more straightforward approach by visually representing the forces using vector addition instead of relying on trigonometry. The importance of showing reasoning and detailed working in problem-solving is emphasized for clarity. Overall, the conversation highlights methods for determining net force and the significance of clear problem-solving steps in physics.
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Homework Statement



The drawing shows three point charges fixed in place. The charge at the coordinate origin has a?
q1 = +8.50 µC; the other two have identical magnitudes, but opposite signs: q2 = -5.00 µC and q3 = +5.00 µC.

http://img66.imageshack.us/my.php?image=p1818mv9.gif

(a) Determine the net force (magnitude and direction) exerted on q1 by the other two charges.

(b) If q1 had a mass of 1.50 g and it were free to move what would be its acceleration?

Homework Equations



F12=k|q1||q2|/r2


F13=k|q1||q2|/r2


The Attempt at a Solution



F12= +2.128*1023

F13= -+2.128*1023

cos(23°)= Fx/+2.13*10^23

Fx= 1.96*1023

cos(23°)= Fy/-2.13*10^23

Fy= -1.77 *1046

Before I go any further, I wanted to make sure I am doing this right since I am kind of rusty. If anyone could check, it would be greatly appreciated.

Thanks in advance!
 
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Your attempt does not show any reasoning nor any working - so I cannot tell if you are doing this right or not.

Note: you can show the image in the post like this:


You look like you've maybe tried to break the forces into x and y components - but why not just draw the vectors head-to-tail? You can see by inspection how their magnitudes and directions are related - which should tell you the direction of the total force without having to do any trig.
 
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