How do I calculate the density of a super critical fluid?

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To calculate the density of a supercritical fluid like xenon, the law of corresponding states and the compressibility factor (z) are essential. For 100 liters of xenon at 23°C and 150 bar, the density is approximately 2015 kg/m³, derived from the compressibility factor, which is influenced by the reduced temperature and pressure. The critical temperature for xenon is 289.7 K, and the critical pressure is 58.4 bar, leading to a calculated compressibility factor of z = 0.40. Various methods exist for calculating z, and users are encouraged to consult resources like the NIST website for accurate fluid properties. Accurate calculations yield a density estimate of around 2000 kg/m³ for xenon under the specified conditions.
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The density of a supercritical fluid
How do I calculate the density of a supercritical fluid? If I have 100 Litres of Xenon at 23°C and 150bar, What will the Xenon in the tank weigh?
The phase diagram is here

https://encyclopedia.airliquide.com/xenon
 
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Look on the NIST website for Xe, under Fluid properties. The answer for your case is 2015 kg/m3.(There is no general equation like PV = nRT to calculate it.)
 
The answer to your question can be determined using the law of corresponding states, based on the compressibility factor z. For xenon, the so-called as centric factor is zero, so the compressibility factor is a function of the reduced temperature and pressure. For xenon, the critical temperature is 289.7 K and 58.4 bars, respectively. So, in this case, the reduced temperature is 296.2/289.7 = 1.02 and the reduced pressure is 150/58.4 = 2.57. From the generalized correlation of compressibility factor as a function of reduced temperature and pressure, this gives a compressibility factor of z = 0.40. Therefore, the number of moles of xenon is $$n=\frac{PV}{zRT}=\frac{(15000000)(0.1)}{(0.40)(8.314)(296.2)}=1523\ moles = 200\ kg$$
So the estimated density is 2000 ##kg/m^3##.
 
Thankyou for your answers great to see you came up with the same answer.

mjc123 said:
Look on the NIST website for Xe, under Fluid properties. The answer for your case is 2015 kg/m3.(There is no general equation like PV = nRT to calculate it.)

Do you have a link for where on the NIST website? I searched for XE on the NIST website and came up with 5109 documents... too many to read through.


Chestermiller said:

n=PVzRT=(15000000)(0.1)(0.40)(8.314)(296.2)=1523 moles=200 kgn=PVzRT=(15000000)(0.1)(0.40)(8.314)(296.2)=1523 moles=200 kg​

n=\frac{PV}{zRT}=\frac{(15000000)(0.1)}{(0.40)(8.314)(296.2)}=1523\ moles = 200\ kg So the estimated density is 2000 kg/m3kg/m3kg/m^3.

I came up with 201 kg so very close, is there a good website or paper that explains this, that I can refer to.

Thanks
 
Google “compressibility factor”
 
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