How Do I Calculate the Maximum Height of a Projectile?

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Homework Help Overview

The discussion revolves around calculating the maximum height of a projectile, focusing on the relationship between initial velocity, launch angle, and time of flight. Participants are exploring the relevant equations and concepts in kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply a kinematic equation for vertical displacement but seeks clarification on determining the time at which the projectile reaches maximum height. Other participants raise questions about the relationship between initial velocity, acceleration, time, and final velocity.

Discussion Status

Some participants have provided equations for calculating maximum height, while others have pointed out potential errors in the expressions used. There is an ongoing exploration of the correct formulation and assumptions related to the projectile's motion.

Contextual Notes

Participants are discussing the implications of different interpretations of the equations, including the correct use of trigonometric functions and factors in the calculations. There is a focus on ensuring the accuracy of the mathematical relationships involved.

Bugsy23
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I need to calculate the maximum height above sea level of a projectile. I already have the values for the initial velocity, the angle and the time of flight, and I have the following equation to calculate the y-component of the displacement from the launch point:
sy=uyt-1/2gt²
But how do I know at what time the projectile has reached its maximum height and begins accelerating downwards?
 
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Bugsy23 said:
I need to calculate the maximum height above sea level of a projectile. I already have the values for the initial velocity, the angle and the time of flight, and I have the following equation to calculate the y-component of the displacement from the launch point:
sy=uyt-1/2gt²
But how do I know at what time the projectile has reached its maximum height and begins accelerating downwards?


Do you know any equations that relate initial velocity, acceleration, time and final velocity?
 
Note the vertical velocity is zero at the maximum height...
 
calculated it... H=(u^2 sin2A)/g
 
Sakriya said:
calculated it... H=(u^2 sin2A)/g

Assuming you meant [itex]sin^2 A[/itex] and not sin(2A) it's correct, except
for a factor (1/2) that you're missing.
 

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