How do I calculate the net resistance in a complex resistor circuit?

AI Thread Summary
To calculate the net resistance in a complex resistor circuit, understanding Wheatstone's principle is crucial, especially when resistors are of equal value. In the discussed circuit, there is no current through resistors 2 and 7, simplifying the calculation. By removing these resistors, the problem can be approached using series and parallel resistance concepts. The first part of the calculation becomes straightforward once these resistors are disregarded. Additional guidance is requested for the more complex second part of the problem.
Spyder22
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I really confused by this circuit: http://myspace.homelinux.com:32123/circuit.jpg
When calculating the net resistance from A to C, how do I know if any current goes through 2 and 7? If there was current going through them, I have clue how they would contribute to the total circuit. For the second question, I don't even know where to start. Obviosly, the net resistance will be a little lower than just 1, but how the heck would you figure out the rest of it?? :confused:
 
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hello buddy ,
you please go and take your physics book and read wheatstones principle. In the given circuit since all resistances are having same value .there is no current in the segment connecting B&D.Now I think it will be eay for you,remove boxes
2 and 7.Using series ,parallel concepts you can solve the first part.(it is just R itself)

The second part is a bit tricky I'll tell it tomarrow
 
Thank you Rohin, I suspected there would be no current through those two resistors, but did not know how to prove it. I will have to read more on the internet about these wheatstone princeples as my book doesn't cover it. This makes the first problem very easy, but if you could provide some suggestions for the second that would be great! :smile:
 
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