How do i find the higher electric field of these two

AI Thread Summary
The discussion focuses on calculating the electric field at the meeting point of a charged ball and an infinite charged pipe, both with the same radius and charge density. Using Gauss's law, the electric field for both shapes is determined to be E = σ/ε₀. Since the ball exhibits spherical symmetry and the pipe cylindrical symmetry, their electric fields at point A, where they touch, are equal in magnitude but opposite in direction. This leads to the conclusion that the total electric field at point A is zero. The calculations and reasoning presented confirm that this outcome makes sense based on the symmetry and charge distribution.
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given a ball and an infinite pipe, both with the same radius and same charge density \sigma
what is the total electric field at the meeting point of the 2 if we bring them close together so that they touch at point A?

what i did was:

the ball has spherical symetry and the pipe has cylindrical symetry, so those are the shapes i will use for my gauss law,

since RA=R

for the ball
\Phi=EA=E(4\PiR2)=\sigma(4\PiR2)/\epsilon0

E=\sigma/\epsilon0

for the pipe
\Phi=EA=E(2\PiR*L)=\sigma2\PiR*L)/\epsilon0

E=\sigma/\epsilon0

does this mean that the total field at point A will be 0 since they have the same field in opposite directions?
does that make sense?
 
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