How Do I Solve These Two Circuit Problems?

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The discussion revolves around solving two circuit problems involving resistors and currents. For the first problem, the equivalent resistance between points A and B is calculated using the formula for resistors in series and parallel, resulting in a resistance value of approximately 49 ohms for R. The second problem involves determining the magnitudes of currents through two resistors, R1 and R2, using the principle of superposition to analyze the circuit with different battery configurations. The user successfully solved both problems and achieved a perfect score on the assignment. This highlights the importance of understanding circuit analysis techniques for solving complex electrical problems.
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Can someone help me with 2 circuit problems...please!

1. The equivalent resistance between points A and B of the resistors shown below is 38 ohms. Find the value of the resistance R.

The resistor looks like this
55 Ohms

_____\/\/\/\/_____
| |
12 Ohms | |
A | |
.____/\/\/\__ | |______. B
| |
| |
|____\/\/\/\/_____|
R

I have no idea what to do...please help.


2. Determine the magnitudes and directions of the currents through R1 and R2, where R1 = 36 ohms and R2 = 10 ohms. I already found the directions. they are both from right to the left, I just need the magnitudes. The Bs represent batteries, and the + next to them indicates the positive side of the battery. I am also really lost on this one can anyone help?

V1=9.0V R1
--+B--/\/\/\-------
| |
| R2 |
.-----/\/\/\/-------.
| |
| |
|----------B+------|
V2=6.0V
 
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I would suggest using [ code ] and [ / code ] tags:
Code:
                             55 Ohms
                       
                      _____\/\/\/\/_____
                      |                 |
       12 Ohms        |                 |
   A                  |                 |
   .____/\/\/\_______ |                 |______. B
                      |                 |
                      |                 |
                      |____\/\/\/\/_____|
                               R

                            
                            V1=9.0V     R1
                               --+B--/\/\/\-------
                               |                  |
                               |         R2       |
                               .-----/\/\/\/-------.
                               |                  |
                               |                  |
                               |----------B+------|
                                          V2=6.0V
EDIT: Well, it looks best in the editor window, slightly better (but not great) in the code tags, and unreadable without those tags.

SECOND EDIT: looks fine now

------------------------------------------------------------

For the first question, you should know how to calculate net resistances when you have resistors in series and parallel. To find the total resistance between A and B, it is:

R_{total} = 12 \Omega + (55 \Omega || R)

38 \Omega = 12 \Omega + (\frac{1}{55 \Omega} + \frac{1}{R})^{-1}

26 \Omega = (\frac{1}{55 \Omega} + \frac{1}{R})^{-1}

(\frac{1}{26 \Omega} - \frac{1}{55 \Omega})^{-1} = R

R \approx 49.310 \Omega

R = 49 \Omega

-----------------------------------------------------------

Solve question 2 using the principle of superposition. That is, find the voltages and currents with the circuit first by replacing the top battery with a short circuit, then find the voltages and currents with the top battery, replacing the bottom with a short circuit. Add the numbers from the first calculations to the second calculations, and make sure you take direction/sign into account.
 
Last edited:
Thank you so much, I got them both right and 100 on the assignment :) :) :)
 
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