How Do Ladder Operators Relate to the 1-D Quantum Harmonic Oscillator?

gronke
Messages
2
Reaction score
0

Homework Statement


ZPryy.jpg



Homework Equations


sSbrM.png



The Attempt at a Solution


I solved part a) correctly, I believe, giving me

ψ = e^{-(√(km)/\hbar)x^{2}}

and a normalization constant A = ((π\hbar)/(km))^{-1/4}

I'm having difficulty with part b. I'm not exactly sure how I create a linear combination. I think I'm supposed to write the linear combination like so:

a + a^{+} = 2(k/2)^{1/2}x

(a + a^{+})(2k^{-1/2}) = x

However, I am not sure how I use the operator methods to show that xψ0 is the first excited state.

If anyone could nudge me in the right direction, I'd be eternally grateful! Thank you.
 
Physics news on Phys.org
What do you get when you calculate ##x\psi_0## with the expression for x you have in terms of the raising and lowering operators?
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top