How Do Suspended Charged Spheres Behave?

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SUMMARY

The discussion focuses on the behavior of two small charged spheres suspended by insulating threads, specifically analyzing the forces acting on them when they are charged. The electrostatic force (F_e) acting on the spheres is established to be equal to mgtan(theta), where m is the mass of the spheres and g is the acceleration due to gravity. The approximation of tan(theta) as d/2L is justified for small angles, leading to the conclusion that the charge q can be expressed as abs(q) = sqrt((mgd^3)/(2kL)), with given values L=70cm, d=4.0cm, and m=0.4g.

PREREQUISITES
  • Understanding of Coulomb's Law and electrostatic forces
  • Basic knowledge of trigonometry, specifically small angle approximations
  • Familiarity with free body diagrams and net force analysis
  • Concepts of mass, gravitational force, and tension in strings
NEXT STEPS
  • Study Coulomb's Law in detail, focusing on its applications in electrostatics
  • Learn about small angle approximations in trigonometry and their implications in physics
  • Explore the derivation and applications of free body diagrams in mechanics
  • Investigate the relationship between tension, mass, and gravitational force in suspended systems
USEFUL FOR

Students studying physics, particularly those focusing on electrostatics and mechanics, as well as educators seeking to explain the principles of charged particles and forces in a classroom setting.

Nevok
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Homework Statement


This is a long one...
Two small spheres with mass m are suspended with insulating threads of length L from a common point. Uncharged, the spheres hang so they touch each other. When given the same charge q they repel each other and hang d distance apart. Assume d is pretty small when compared to L but not the the diameter of the spheres.

a) Explain, using a net force diagram, why the magnitude of the electrostatic force F_e acting on the spheres must be equal to mgtan(theta)

b) Explain why in this situation we can approximate tan(theta) as d/2L and what the percent error if d=L/10

c)Combine the answers to part a and b with Coulombs law to show that abs(q)= sqrt((mgd^3)/(2kL))
L=70cm, d=4.0cm m=0.4g

Homework Equations


Coulombs law, F_e=(k(q_1*q_2))/r^2.

The Attempt at a Solution


Well, I have part a, but i have no clue about why you could do that approximation.
 
Last edited:
Physics news on Phys.org
Hello nevok. For really small angles, \sin \theta \approx \tan \theta
 
Thanks, with that and a little bit of thinking I solved it.
 

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