How Do You Analyze Motion Using V-T Graphs?

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SUMMARY

This discussion focuses on analyzing motion using velocity-time (V-T) graphs, specifically addressing calculations of displacement, velocity, and acceleration based on provided data. The user outlines a method to calculate initial velocity using the equation s = ut + (at²)/2, emphasizing that the initial velocity is not zero due to the cart's state before time t=0. The conversation concludes with a confirmation that the area under the V-T graph will yield the total displacement of 140 cm, provided the initial velocity is accounted for in the calculations.

PREREQUISITES
  • Understanding of kinematic equations, specifically s = ut + (at²)/2
  • Familiarity with velocity-time graph interpretation
  • Basic arithmetic skills for calculations
  • Knowledge of displacement and acceleration concepts
NEXT STEPS
  • Learn how to derive initial velocity from kinematic equations
  • Study the relationship between area under a V-T graph and displacement
  • Explore advanced kinematic concepts, including instantaneous acceleration
  • Practice sketching and analyzing V-T graphs with varying initial conditions
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators looking for practical examples of motion analysis using V-T graphs.

Dazed
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Homework Statement



distance (cm) 0.0 5.0 15.0 30.0 50.0 75.0 105.0 140.0
time (s) 0.0 0.1 0.2 0.3 0.4 0.50 0.6 0.7

a. calculating the displacement during each time interval. Add to the above table of data.

b. calculating the velocity of the cart during each time interval. Add to the above table of data.

c. sketching a velocity-time graph.

d. calculating the acceleration of the object from the velocity-time graph.

e. Using the velocity-time graph to calculate the total displacement of the cart.


Homework Equations





The Attempt at a Solution



http://www.freewebs.com/dazed42/phys.htm
 
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Ok, you've used the right method, and therefore the answer will be correct as long as you've not made any arithmetical errors. The reason for the displacement not equalling the total distance measured will be the same as the previous question, namely that the velocity of the truck at t=0 was no zero.

So, you can use the equation given in the last question to calculate the initial velocity. Recall s=ut+(at^2)/2. Put s=140, t is the total time (0.7s) and a is the acceleration you have calculated.

Really, for the question, you just need to state the the truck was not at rest at t=0, but if you want to check, you can calculate u from the above equation, then add it to each value of v on the graph, giving you a new graph, for which the area underneath will add up to 140cm
 
Thanks buddy. From the phrasing of the question I was given the impression that the initial velocity could not be zero. (the cart is at rest before 0 and released at 0, so there must be some instantaneous acceleration)

Much thanks for all the help, I'll be glad to put this behind me now. (Until finals.. whee)

peace,
Dazed
 

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