How Do You Calculate the Coefficient of Kinetic Friction on an Incline?

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To calculate the coefficient of kinetic friction on a 30° incline with a block sliding at 1.2 m/s², one must analyze the forces acting on the block. The gravitational force components must be resolved into tangential and normal directions relative to the incline. Since the block is already sliding, the coefficient of static friction is not applicable; instead, the focus should be on the coefficient of kinetic friction. The normal force and the net force acting on the block in the direction of motion are crucial for this calculation. Understanding these dynamics is essential for determining the coefficient accurately.
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A block is sliding down a 30° incline at 1.2ms^-2
Find the coefficient of static friction.
[g=9.8ms^2]

I am stumped..

Some relevant equations:
Fr = μ(Fn)
Fn = mg

Ultimately I got μ=0.5 ---> This was through mashing and playing with some trig.
 
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Bradyns said:
A block is sliding down a 30° incline at 1.2ms^-2
Find the coefficient of static friction.
[g=9.8ms^2]

I am stumped..

I got μ=0.5

If the block is already sliding down the incline, then you don't have the information you need to determine the coefficient of static friction. On the other hand, you do have the information you need to determine the coefficient of kinetic friction. What are the components of the gravitational force on the block in the directions tangent and normal to the incline? Is the block accelerating in the direction normal to the incline? Is the block accelerating in the direction tangent to the incline? What are the force components acting on the block in the direction tangent to the incline? What is the normal force exerted by the incline on the block?
 
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