How Do You Calculate the Damping Constant for a Spring-Mass System?

AI Thread Summary
To calculate the damping constant b for a spring-mass system, the equation x(t) = Xm e^(-bt/2m) cos(ωt) is used, where Xm is the initial displacement, m is the mass, and ω is the angular frequency. Given the mass of the egg is 0.045 kg, the spring constant k is 24.7 N/m, and the amplitude decreases from 0.290 m to 0.120 m over 5.10 seconds, the values can be substituted into the equation. The angular frequency ω is calculated using ω = √(k/m). The discussion highlights the need for correct substitution of values to find the damping constant b accurately. Understanding the relationship between displacement, time, and damping is crucial for solving the problem.
jaymode
Messages
26
Reaction score
0
Here is my problem:
A hard-boiled egg of mass 45.0 g moves on the end of a spring with force constant k = 24.7 N/m. Its initial displacement is 0.290 m. A damping force F = - bv acts on the egg, and the amplitude of the motion decreases to 0.120 m in a time of 5.10 s.


I need to find the magnitude of the dampening constant b.

I am completely clueless on how to approach this question.

edit: corrected some stuff.
 
Last edited:
Physics news on Phys.org
Me too, since I do not know what you mean by 'the force of B'.
 
sorry i guess i typed it wrong. the dampening force:

F = -bv

I need to find the magnitude of the dampening constant b.
 
x(t) = x_{m} e^{\frac{-bt}{2m}} cos( \omega t)

where Xm is the initial displacement
b is hte damping force
m is the mass
omega is the angular frequency \omega = \frac{2 \pi}{T} where T = 2 \pi \sqrt{\frac{m}{k}}
 
for some reason that is not working for me.
 
jaymode said:
for some reason that is not working for me.
perhaps you are not using your numbers correctly

initla displacement Xm = 0.290 m
k = 24.7 N/m
X(5.10) = 0.120 m
t = 5.10s
m = 45g = 0.045 kg
and omega = \sqrt{\frac{m}{k}}
it's blind substitution, really
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top