How Do You Calculate the Third Maximum Position in Single Slit Diffraction?

AI Thread Summary
The calculation for the position of the third maximum in single slit diffraction using a helium-neon laser with a wavelength of 633 nm and a slit width of 2.2 x 10^-5 m is correct. The formula used is Sin Theta(m) = (m + 0.5) Lambda/w. Substituting the values for m=3 results in Sin Theta(3) = 0.1, leading to Theta(3) = sin-1(0.1), which equals 5.7 degrees. Thus, the position of the third maximum is indeed at 5.7 degrees.
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A single slit is illuminated with a helium-neon laser whose wavelength is 633 nm. If the slit width is 2.2 x 10 e-5 m, calculate the position of the third maximum in degrees


2. Homework Equations

Sin Theta(m) = (m + 0.5) Lambda/w

3. The Attempt at a Solution

Sin Theta(3) = (3 + 0.5)(633 x 10 e-9)/2.2 x 10 e-5
=(3.5)(633 x 10 e-9)/2.2 x 10 e-5
=0.1

Theta(3) = sin-1(0.1)
=5.7 degrees

Therefore, the position of the third maximum is at 5.7 degrees


is this right?!
 
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alicia113 said:
A single slit is illuminated with a helium-neon laser whose wavelength is 633 nm. If the slit width is 2.2 x 10 e-5 m, calculate the position of the third maximum in degrees

2. Homework Equations

Sin Theta(m) = (m + 0.5) Lambda/w

3. The Attempt at a Solution

Sin Theta(3) = (3 + 0.5)(633 x 10 e-9)/2.2 x 10 e-5
=(3.5)(633 x 10 e-9)/2.2 x 10 e-5
=0.1

Theta(3) = sin-1(0.1)
=5.7 degrees

Therefore, the position of the third maximum is at 5.7 degrees

is this right?!
That looks good to me.
 
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