How do you evaluate the square and products of 5e^(3(pi)i)/4 in polar form?

seboastien
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Homework Statement


Evaluate the square 0f 5e^(3(pi)i)/4 without using Cartesian form, and also the three different products.


Homework Equations


e^i(theta) = cos(theta) + isin(theta)?


The Attempt at a Solution


I have absolutely no idea here, nothing in my notes even begins to suggest how I can answer this.
 
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All you really need to know is the equation you listed. The square of e^x is (e^x)^2=e^(2x), use this information to solve your problem.
 
yes but what do they mean by the 3 products?
 
With not using the three products I would guess they mean to not use:

<br /> (\cos x+i\sin x)^2=\cos^2x-\sin^2 x+2i\cos x \sin x<br />
 
it says to evaluate the three products of the complex number
 
Then just remove the 'nots' in my previous post.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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