How Do You Rotate and Stretch a Complex Number Vector?

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To rotate the vector A(2√3,1) by 30° clockwise and stretch it by a factor of 6, the argument of the vector must first be calculated, which is approximately 16.1°. After rotating, the new angle becomes approximately -13.9°. The rotation can be represented using complex multiplication by a corresponding complex number. The final coordinates of point B can be expressed in surd form without needing to convert to decimal or radians. The focus should remain on exact representations involving square roots.
AlexChan
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Given A(2√3,1) in R^2 , rotate OA by 30° in clockwise direction and stretch the resulting vector by a factor of 6 to OB. Determine the coordinates of B in surd form using complex number technique.

i try to rewrite in Euler's form and I found the modulus was √13 but the argument could not be represented in radian, so i feel confuse to cope with this question.:frown:

MENTOR Note: moved here from Linear Algebra hence no template
 
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Did you try drawing it to see where you went wrong?
 
jedishrfu said:
Did you try drawing it to see where you went wrong?

yes, i draw the it in 2d plane with real and img. axis and roughly get the resulting vector, but still confuse with getting the exact number of the argument
 
Can you show us what you did step by step?

On this site,we can't help you unless you show some work.
 
jedishrfu said:
Can you show us what you did step by step?

On this site,we can't help you unless you show some work.
1.PNG

sorry for my bad work.
the above is the roughly work. I found the angle(argument) between OA and x-axis (real axis) was tan^-1(1/2√3)≈16.10211375
After rotate 30° clockwise, the angle between OB and x-axis was 16.10211375-30≈-13.89788625
and here i got trouble with the representation in surd form.
OA = 2√3+i =√13(cos16.10211375+isin16.10211375)
I found that complex number multiplication represent scaling and rotation, but my notes didnt contain explanation of this part
 
So the rotated number is sqrt(13)*(cos(-13.89) + I sin(-13.89) ) right?

Then take the negative out of the sin and cos to get it into better form.

Next you have to make it 6 times bigger.
 
AlexChan said:
Given A(2√3,1) in R^2 , rotate OA by 30° in clockwise direction and stretch the resulting vector by a factor of 6 to OB. Determine the coordinates of B in surd form using complex number technique.

i try to rewrite in Euler's form and I found the modulus was √13 but the argument could not be represented in radian, so i feel confuse to cope with this question.:frown:

MENTOR Note: moved here from Linear Algebra hence no template

The argument can be expressed in radians, but you need not bother doing that. Just express the clockwise 30° rotation as multiplication by a complex number of the form a + bi and then carry out the operations of standard complex-number multiplication. Your final answer need not involve any approximate decimal numbers, but can be expressed exactly in terms of square roots and the like.
 
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