How Do You Solve a Circuit with Four Meshes Using Mesh Analysis?

AI Thread Summary
The discussion centers on solving a circuit with four meshes using mesh analysis. The user outlines their approach by defining loop currents and applying Kirchhoff's Voltage Law (KVL) to each loop. They derive equations for the loops, particularly focusing on the supermesh created by the shared current source. Feedback indicates that the user's assumption about the current I_0 is incorrect, as it should be a combination of currents from two meshes rather than equal to I_3. The conversation emphasizes the importance of accurately setting up equations and understanding current flow between meshes.
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Mesh Analysis -- (4 meshes)

Homework Statement



http://img185.imageshack.us/img185/1541/screenshot01ly9.jpg

Homework Equations



V=IR
KVL

The Attempt at a Solution



Loop 1 is the top left loop.
Loop 2 is the top right loop.
Loop 3 is the bottom right loop.
Loop 4 is the bottom left loop.
(Think of the quadrants in the cartesian coordinate system... that's my loop and loop currents).

Loop currents are going in the CW direction.

For Loop 1:

-14 + I_1 + (I_1 - I_2) + (I_1 - I_4) = 0

For Loop 2:

I_2 = 2mA

For Loop 3 & 4:

Since they are super meshes because of the shared current source... this is what I have:

4mA = I_3 - I_4
-- and --
using the supermesh idea, and short-circuiting the shared 4mA current source...

I4 + 2*I3 + I3 + I4 = 0... which is 3I_3 + 2I_4 = 0

Is my setup correct?

If so, this is what I did...

solved for I_4 in the equation 3I_3 + 2I_4 = 0... I_4 = (-3I_3) / 2

I plugged that I_4 into the eq. 4mA = I_3 - I_4... and I got I_3 = 2mA.

I assumed I_0, what we're trying to find, is equal to I_3. Is this a valid assumption since the current is going around that mesh?
 
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Your supermesh equation is incorrect. Starting from the lower left it should be 1k*i_4 + 1k*(i_4 - i_1) + 2k*(i_3 - i_2) + 1k*i_3 = 0

Because of that, your assumption about I_0 is also wrong. The current in that branch is flowing between meshes 2 and 3, so the current is a combination of the two: I_0 = I_3 - I_2.
 

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