How Do You Solve for Acceleration and Tension in a Pulley System?

gen007
Messages
2
Reaction score
0

Homework Statement



http://img69.imageshack.us/img69/2429/phyq1.jpg

Homework Equations


to find the acceleration of the 2 objects and the Tension Force.


The Attempt at a Solution



since only 1 pulley used, a=a1=a2, then
m1a=T (1)
m2a=-T+m2gsin45 (2)

i wonder what happen to the m2gcos 45?? and is the 2 equations right for my assumption? thanks
 
Last edited by a moderator:
Physics news on Phys.org
m2gcos45 is the normal force applied by m2, which isn't really important unless friction is considered (or unless it's so big that something breaks).
 
but is the 2 equations right? because i am still ponder over m2a=-T+m2gsin45 or m2a=T+m2gsin45 ?? really sad my basic wasnt good...
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...

Similar threads

Back
Top