How Do You Solve Related Rates Problems in Calculus?

AI Thread Summary
To solve related rates problems in calculus, start by identifying and writing down the given variables mathematically. For example, in a problem involving a kite, you can model the situation with a right triangle where the height is constant at 300 ft and the horizontal leg is variable. Given the rate of change of the horizontal leg (dx/dt = 25 ft/s), you can find the rate of change of the string length (ds/dt) using the chain rule. By establishing a relationship between the string length and the horizontal distance, you can differentiate to find the missing rate at a specific point. Understanding these relationships is crucial for solving related rates problems effectively.
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Hi, I have no clue on how to work these problems out. Due tomorrow, please help! Thanks.

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The first step is to always identify and write down the given variables mathematically.
For question 14, you can draw a right-triangle with Inge at the ground vertex, and the kite at the top vertex. The string is the hypotenuse, so the height of the kite above the ground is the vertical leg which is 300ft. The length of the horizontal leg is variable with time, we'll call it x. We are given dx/dt = 25 ft/s. We want to find ds/dt when x=500ft, where s is the length of the string. We note that ds/dt = (ds/dx)(dx/dt) by the chain rule. Thus, if we write a function s = s(x) and differentiate it at x = 500ft, we will have the missing rate in our equation. Can you find an equation relating s and x ?
 
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A little late, eh? Have you done any work on these? We're here to help you learn how to solve problems, not give you answers.

P.S. please don't spam.
 
hypermorphism said:
The first step is to always identify and write down the given variables mathematically.
For question 14, you can draw a right-triangle with Inge at the ground vertex, and the kite at the top vertex. The string is the hypotenuse, so the height of the kite above the ground is the vertical leg which is 300ft. The length of the horizontal leg is variable with time, we'll call it x. We are given dx/dt = 25 ft/s. We want to find ds/dt when x=500ft, where s is the length of the string. We note that ds/dt = (ds/dx)(dx/dt) by the chain rule. Thus, if we write a function s = s(x) and differentiate it at x = 500ft, we will have the missing rate in our equation. Can you find an equation relating s and x ?

Thanks! :smile:
 
Hurkyl said:
A little late, eh? Have you done any work on these? We're here to help you learn how to solve problems, not give you answers.

P.S. please don't spam.

Haha, yeah... a little late. But I've done some work on these.

P.S. Sorry. =/
 
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