How Do You Solve This Capacitor Problem with Aluminum Electrodes?

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SUMMARY

The problem involves calculating the capacitance of two 5.0-cm-diameter aluminum electrodes spaced 0.50 mm apart and connected to a 200 V battery. The correct formula for capacitance is C = εA/d, where ε is the permittivity of free space (8.85 x 10^-12 F/m), A is the area of the electrodes, and d is the distance between them. The area was calculated using the formula A = π(d^2)/4, leading to a capacitance of approximately 139 pF. The initial calculation error stemmed from incorrect area computation.

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Homework Statement


Two 5.0-cm-diameter aluminum electrodes are spaced 0.50 mm apart. The electrodes are connected to a 200 V battery.

Homework Equations


C = εA/d

The Attempt at a Solution


So for my solution I took the area of the plate, ((.052π) * 8.85*10-12) / .5*10-3 and I got an answer of 1.39 * 10-10 F or 139 pF. The website the homework is done through is saying this is wrong. not too sure where the mistake is...
 
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Area of electrode = pi * d^2 /4

Looks like you used pi * d^2
 

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