- #1
lmlgrey
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1. For the modified Atwood machine of this problem, assume that the two masses do move. Also assume that there is no friction, and that gravity is the only force acting. Also assume that you can ignore the mass of the pulleys and of the connecting rod and string. Notice that mass m1 is rigidly attached to the smaller pulley.
Do this problem in 3 stages, by answering the following questions.
1. The total force acting on mass m1 and that acting on mass m2 areboth zero TF
2. in the same direction TF
3. equal in magnitude TFhttp://b.imagehost.org/0304/lerner3_53.gif [/URL]
3. my guess is that since the tension force is the same everywhere on this massless string, then the total force acting on mass m1 and m2 should be both zero... but its known whether the pulleys are in motion or not so...
Do this problem in 3 stages, by answering the following questions.
1. The total force acting on mass m1 and that acting on mass m2 areboth zero TF
2. in the same direction TF
3. equal in magnitude TFhttp://b.imagehost.org/0304/lerner3_53.gif [/URL]
3. my guess is that since the tension force is the same everywhere on this massless string, then the total force acting on mass m1 and m2 should be both zero... but its known whether the pulleys are in motion or not so...
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