How Does an Object Behave on a 30° Slope After an Initial Upward Force?

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An object on a 30° slope initially moves upward at 2.5 m/s before coming to a stop due to gravitational forces. To determine how far it travels upward, one must calculate the conversion of kinetic energy into gravitational potential energy, considering the slope's angle. The object will slide back down because the force of gravity exceeds the force of friction once it stops. The discussion emphasizes the balance of forces and energy transformations involved in the object's motion. Understanding these principles is crucial for solving similar physics problems.
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Homework Statement


An object slides down a 30° angled slope with even velocity.
The object is hit with a force such that its initial velocity is now 2,5m/s up the slope. How far does the object go before coming to a stop (I answered this, though) and how much of the kinetic energy becomes potential energy? Does the object slide back down? If so, why?


Homework Equations


Work and force equations


The Attempt at a Solution


I can answer how far it went but I'm unsure on where to begin on the rest!
 
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For the first part, you want to consider how much kinetic energy it has to start (with the 2.5 m/s velocity), and then how far vertically it moves up the slope, which would contribute to gravitational potential energy. That would use the distance it travels along the slope in addition to the angle of the slope.

For the last part, you want to consider how the force of friction acting up the slope compares to the force of gravity, which acts down the slope. You know that by sliding down with constant velocity, the forces must be equal, so how do you think they will compare when the block is at rest?
 
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