How does calculus of variations handle explicit time dependence in Lagrangian?

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Discussion Overview

The discussion centers on how calculus of variations addresses explicit time dependence in Lagrangians, particularly in the context of the Least Action Principle. Participants explore the implications of time-dependent Lagrangians and the treatment of terms involving time in the variational formulation.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant questions how explicit time dependence in the Lagrangian affects the derivation of the Euler-Lagrange equations, particularly regarding the term ∂L/∂t δt.
  • Another participant asserts that the Least Action Principle applies to time-dependent Lagrangians similarly to time-independent ones, but does not clarify how the term ∂L/∂t δt is treated.
  • A request for clarification is made regarding the handling of the term ∂L/∂t δt in the context of the Least Action Principle.
  • It is mentioned that this term does not appear in the Least Action formulation because the endpoints of the interval are not varied.
  • A calculation is suggested to demonstrate that the term does not arise when applying the variational principle under certain conditions for h(t).
  • One participant notes that the term arises from the chain rule of δL and expresses that the presentation of the Least Action Principle may be misleading.
  • Another participant adds that the Action functional does not necessarily attain a minimum for real motion, indicating that real motion is merely a critical point of the functional.

Areas of Agreement / Disagreement

Participants express differing views on the treatment of explicit time dependence in the Lagrangian and the implications for the Least Action Principle. There is no consensus on how the term ∂L/∂t δt should be handled, and the discussion remains unresolved.

Contextual Notes

Some participants emphasize the importance of the specific conditions under which the variational principle is applied, particularly regarding the treatment of endpoints and the nature of the Action functional.

DuckAmuck
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If a Lagrangian has explicit time dependence due to the potential changing, or thrust being applied to the object in question, how does calculus of variations handle this?

It's easy to get the Lagrange equations from:

δL = ∂L/∂x δx + ∂L/∂ δ

What is not clear is how this works when t is an explicit variable in L

δL = ∂L/∂x δx + ∂L/∂ δ + ∂L/∂t δt

How does this still result in:

∂L/∂x = d/dt ∂L/∂ẋ ?
 
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if you mean the standard Least Action Principle then this principle holds for time dependent Lagrangians by the same way as for time independent Lagrangians
 
wrobel said:
if you mean the standard Least Action Principle then this principle holds for time dependent Lagrangians by the same way as for time independent Lagrangians

Can you show why? How is the term ∂L/∂t δt handled in Least Action?
 
DuckAmuck said:
How is the term ∂L/∂t δt handled in Least Action?
the is no such a term in Least Action because you do not vary ends of the interval
 
Just calculate this: $$\frac{d}{d\epsilon}\Big|_{\epsilon=0}\int_{t_1}^{t_2}L(t,q(t)+\epsilon h(t),\dot q(t)+\epsilon \dot h(t))dt$$ for ##h(t)## such that ##h(t_i)=0,\quad i=1,2##
you will not get that term
 
That term comes from the chain rule of δL
I have seen the least action principle shown as 0 = δS = ∫δL dt, which I guess is misleading.
I have seen the form you have, and that makes more sense. You are explicitly minimizing with respect to epsilon.
 
By the way the Action functional is not compelled to attain a minimum for real motion, real motion is just a critical point of this functional . It can attain maximum for real motion
 
Last edited:
DuckAmuck said:
That term comes from the chain rule of δL
I have seen the least action principle shown as 0 = δS = ∫δL dt, which I guess is misleading.
I have seen the form you have, and that makes more sense. You are explicitly minimizing with respect to epsilon.
By definition time is not varied in the usual Hamilton principle!
 

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