How Does Changing Mass, Length, or Gravity Affect a Pendulum's Period?

AI Thread Summary
The period of a pendulum is influenced by its length and the acceleration due to gravity, but not by its mass. Doubling the length of the pendulum increases its period, calculated using the formula T = 2π * sqrt(L/g). When the pendulum is moved to a planet with a gravitational acceleration of 16 m/s², the period can be recalculated using the same formula. The original period of 1.8 seconds will change based on these adjustments. Understanding these relationships is crucial for predicting pendulum behavior under varying conditions.
confused1
Messages
21
Reaction score
0
A pendulum has a period of 1.8 s.

a) Its mass is doubled. What is its period now?


b) Its length is doubled. What is its period now?


The original pendulum is taken to a planet where g = 16 m/s2.
c) What is its period on that planet?
 
Physics news on Phys.org
So what's the equation for the period of a simple pendulum
 
T = 2*pi / w. What is w for a simple pendulum?
 
T = 2 * Pi * sqrt( L/g )
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top