How Does Doubling Internal Energy Affect Pressure in a Sealed Container?

AI Thread Summary
Doubling the internal energy in a sealed container affects pressure when volume remains constant, as it leads to an increase in temperature. According to the ideal gas law, pressure is directly proportional to temperature when volume is fixed. Therefore, if internal energy is increased, the pressure would also increase, potentially doubling if the initial conditions allow for it. The discussion emphasizes the relationship between internal energy, temperature, and pressure, particularly in the context of ideal gases. Understanding these principles is crucial for solving related physics problems.
ab94
Messages
11
Reaction score
0

Homework Statement


For example in the problem if we have a volume of 10L at 15 degrees Celsius, and there is initially 100Pascals pressure, what would the final pressure be if we double the Internal Energy?


Homework Equations


U=3/2nRT


The Attempt at a Solution


I though pressure was independent of Internal Energy so it would remain unchanged? but Idk
 
Physics news on Phys.org
ab94 said:
I thought pressure was independent of Internal Energy so it would remain unchanged? but Idk
If you change the volume, and hence the pressure, isothermally then the internal energy will not change. But if the volume stays the same then pressure and temperature can only vary if the other does too. Here, internal energy is being increased, so the temperature is going up, but the volume stays the same. So what happens to the pressure?
 
The pressure would also double?
 
ab94 said:
The pressure would also double?
It depends. Is this an ideal gas? Can you explain your answer in terms of the ideal gas law?

AM
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top