How Does Electric Flux Calculation Apply to Complex Fields and Geometries?

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SUMMARY

The discussion focuses on calculating electric flux and net charge within complex geometries, specifically a cube and concentric spheres in varying electric fields. The electric field is defined as E = (91.2x^2 - 2.9)i, and the relevant equation for flux is ∮E*dA = Q/ε0. Participants seek clarification on how to apply this equation given that the electric field is not constant and how to determine the charge on the outer surface of the second sphere, which involves understanding the electric field within conducting materials.

PREREQUISITES
  • Understanding of electric fields and flux calculations
  • Familiarity with Gauss's Law and its applications
  • Knowledge of charge distribution in conductors
  • Basic geometry of three-dimensional shapes, particularly cubes and spheres
NEXT STEPS
  • Study the application of Gauss's Law in non-uniform electric fields
  • Learn about electric field calculations in spherical coordinates
  • Explore the properties of conductors in electrostatic equilibrium
  • Investigate the relationship between charge and electric field strength in complex geometries
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Students and professionals in physics, electrical engineering, and anyone involved in electrostatics or electric field analysis, particularly those tackling complex geometrical configurations.

psysicsfeet
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Homework Statement


1)
A large cube has its bottom face on the x-z plane and its back face on the x-y plane. The corners on the x-axis are at (3.39 m,0,0) and (12.3 m,0,0). The cube is immersed in an electric field pointing in the positive x-direction, and given by:

E = (91.2x^2 - 2.9)i, x is the distance along the x-axis in m, and E is in N/C.

Find the net charge Q inside the cube, in μC.

2)
There are two hollow, conducting, concentric spheres, with air between the spheres:

-Sphere 1 is the inner sphere; it has inner radius a = 2.35 mm, outer radius b = 8.53 mm, and carries charge Q1 = -8.41 pC.

- Sphere 2 is the outer sphere; it has inner radius c = 3.58 cm, outer radius d = 7.92 cm, and carries charge Q2 = 5.84 pC.

- At the common center is point charge Q = -7.21 pC.

Find the charge on the outer surface of sphere 2, in pC.

Homework Equations


∮E*dA = Q/E0

The Attempt at a Solution


Q 1) I try to use equation ∮E*dA = Q/E0 to solve first question, but what I am confusing is the variable E is not a constant, should I plug in the value of x to solve it? and for the surface area since it is a cube, I should count as 6r^2? r is the slice length of the cube.
Q 2) I guess it is a simple question but I just can not figure out the relationship between two spheres.

thank you for help.
 
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psysicsfeet said:
thank you SammyS. can you give me some hints for second question?
What is the electric field within the conducting material itself?
 
SammyS said:
What is the electric field within the conducting material itself?
within the conducting material itself. do you mean inside the inner radius of inner cycle? is it kQ/a^2?
 
psysicsfeet said:
within the conducting material itself. do you mean inside the inner radius of inner cycle? is it kQ/a^2?
I mean: within the conducting material itself, for either of the shells in this problem.
 

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