How Does Inserting a Dielectric Affect Voltage in an Uncharged Capacitor?

AI Thread Summary
Inserting a dielectric into an uncharged capacitor decreases the voltage because it reduces the net electric field between the conductors. The presence of the dielectric increases the capacitance while keeping the charge constant, leading to a lower voltage according to the formula V=Q/C. This phenomenon is also influenced by the dielectric's properties, specifically its polarization, which further contributes to the decrease in voltage. The discussion emphasizes the relationship between capacitance, charge, and voltage in the context of dielectrics. Understanding these principles is crucial for comprehending capacitor behavior in electrical circuits.
Gear300
Messages
1,209
Reaction score
9
For a capacitor not connected to a battery, why does the voltage decrease with the insertion of a dielectric. Would it be because the net electric field between the conductors is decreased?
 
Physics news on Phys.org
you just answered your own question. there is also less room for particles to lose potential over.
 
username2 said:
you just answered your own question. there is also less room for particles to lose potential over.

Gear300, your answer is a lot better than this one. Yes, the dielectric decreases the electric field. What do you mean "less room"?
 
alternative method :
Q=CV
V=Q/C

insert a dielectric , keeping the charge accumulated unchanged. the greater the dielectric(coefficient e), the greater the capacitance and the lower the voltage across

but why. it is related to the properties of dielectric ... and polarization makes the V decreases as well as ... that's another story
 
  • Like
Likes gracy
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top