How Does Particle Motion on an XY Plane Change Over Time?

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The particle's acceleration on the xy plane is defined as a=3ti + 4tj, affecting its motion over time. At t=0, the initial position is r=(20.0m)i + (40.0m)j and the initial velocity is v=(5.00m/s)i +(2.00m/s)j. To determine the position vector at t=4.00 s, the problem should be approached by treating the x and y components separately. After calculating the individual positions for both axes, the overall position can be reconstructed, and a visual representation can assist in finding the angle of travel relative to the positive x-axis. This methodical breakdown simplifies the analysis of the particle's motion over time.
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The acceleration of a particle on a horizontal xy plane is given by a=3ti + 4tj, where a is in meters per second-squared and t is in sec. At t=0, the particle has the position vector r=(20.0m)i + (40.0m)j and the velocity vector
v=(5.00m/s)i +(2.00m/s)j. At t=4.00 s, what are its position vector in unit-vector notation and the angle between its direction of travel and the positive direction of the x axis?
 
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I'll say the same thing here as in the other problem: treat the axis as separate problems, solve both, then put the problem back together. By this point in class you've done 1d problems plenty - break this down into two separate 1d problems, figure out the i and j positions, then draw a picture of where the particle is and find the angle.
 
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