How Does Pressure Affect Seawater Volume and Density in the Mariana Trench?

  • Thread starter Thread starter physics_geek
  • Start date Start date
  • Tags Tags
    Elastic Solids
AI Thread Summary
Pressure significantly affects seawater volume and density in the Mariana Trench due to the immense depth of approximately 11 km, resulting in a pressure of about 1.13 x 10^8 N/m². The bulk modulus of seawater is given as 2.34 x 10^9 N/m², which is essential for calculating changes in volume. The initial attempt to calculate the volume change of 1.2 m³ of seawater resulted in an incorrect value of 0.0579 m³, which was later corrected to -0.0579 m³ to indicate a decrease in volume. The density of seawater at the surface is 1.03 x 10^3 kg/m³, and the discussion confirms that the density at the bottom was successfully calculated. Understanding these principles is crucial for grasping the effects of pressure on seawater in deep ocean environments.
physics_geek
Messages
82
Reaction score
0

Homework Statement


The deepest point in any ocean is in the Mariana Trench, which is about 11 km deep, in the Pacific. The pressure at this depth is huge, about 1.13 108 N/m2. (Take the bulk modulus of seawater to be 2.34 109 N/m2)
(a) Calculate the change in volume of 1.2 m3 of seawater carried from the surface to this deepest point.
(b) The density of seawater at the surface is 1.03 103 kg/m3. Find its density at the bottom.


Homework Equations


B = changeP/(changevolume/Vinitial)

or change_volume = Vinitial(change_p)/B


The Attempt at a Solution


im not sure if for part a i just plug in the numbers they give..im getting like .0579 m^3 but that's wrong
any help?
 
Physics news on Phys.org
How did one determine that 0.0579 m3 is the wrong answer. Perhaps it should also have a - sign to indicate a decrease in volume, but the magnitude is right.
 
ok yea it was -.0579 I am sorry
do you know how to do part b?
 
nvm..i got part b
thanks for your help
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top