How far did the man walk and what was his average speed?

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AI Thread Summary
The discussion revolves around calculating the total distance, displacement, average speed, and average velocity of a man who walked two segments: 440 m at 50 degrees and 580 m at 185 degrees, taking 150 minutes. The total distance traveled is confirmed to be 1020 m, but the displacement is not equal to this distance due to the directional components of the walk. The average speed is calculated as 6.8 m/min, while the average velocity requires determining the resultant displacement, which is suggested to be around 286.5 m. The conversation highlights the importance of distinguishing between scalar and vector quantities in these calculations. Understanding how to graphically represent the walk and calculate displacement is emphasized for accurate results.
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Homework Statement



A man walked 440 m 50 degrees polar positive, and then 580 m 185 degrees polar positive. The entire trip took 150 min.

Total distance travelled?
The displacement of the man?
Average of the man in m/min?
Average velocity of the man in m/min?

Homework Equations



Speed=Total Distance/Total Time
Average velocity=Displacement/Total Time

The Attempt at a Solution



I graphed this out. I was accustomed to distance being N/S/W/E. Distance is a scalar quantity so it doesn't really into account positive and negative.

Would my total distance traveled be 1020 m?

Help please?

c. 1020 m/150 mins=6.8 m/s
 
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a. Correct. The man walked 440m then 580m so he walked a total of 1020m.
b. However at the end of his walk he is not 1020m from his starting point. So how far is he?
c. You are correct.
d. Velocity is a vector quantity. We need the sum of his two velocity vectors. Or more simply the displacement from question b divided by the total time.
 
I'm confused as how to calculate displacement for this, can you give me an example please?
 
C would actually be 6.8m/min...just a small mistake but you might lose marks :P
 
To calculate the displacement you can make a triangle and have the hypotenus be his distance, then you can do 440 sin 50 degrees as his first displacement, and then I believe you would add to that 580 sin 185 degrees (which would be a negative number)...I believe his total displacement would be 286.5 m...I'm not positive though.
 
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