How far is the object from the mirror and what is the curvature?

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An object placed 15 cm from a mirror produces an upright, virtual image that is half its size. The image distance is calculated to be -7.5 cm from the mirror. Using the mirror equation, the focal length is determined to be -15 cm. Consequently, the radius of curvature is found to be -30 cm. The calculations clarify the relationship between object distance, image distance, and mirror curvature.
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Homework Statement



An object is placed 15cm from a certain mirror, the image is half the size of the object, upright, and virtual. how far is the image fromt he mirror, and what is the radius of curavature of the mirror?

Homework Equations


1/f = 1/p + 1/q

f= r/2


The Attempt at a Solution


1/f = 1/p + 1/q
1/15= 1/-7.5

1/q = 1/5cm

f= r/2
r=f*2
15*2= 30cm
 
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1/f = 1/p + 1/q
1/15= 1/-7.5
This step is wrong.
It should be
1/f = 1/p + 1/q
1/f = 1/15 + 1/-7.5
 


so base on what was corrected the answer is -1/15cm is how far is the image from the mirror, and what is the radius of curavature of the mirror is f= r/2
r=f*2
-1/15*2= -2/15cm?
 


oh i mean -30cm for r
 


Yes.
 
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