How long does it take for the sun to move its own diameter?

AI Thread Summary
The sun's apparent movement across the sky is due to the Earth's rotation. To determine how long it takes for the sun to move a distance equal to its diameter, one must convert the subtended angle from radians to degrees and calculate the angular speed of the observer on Earth. The sun completes a full rotation of 2π radians in one day, which can be converted to radians per second. By knowing the angular speed and the distance in radians, the time required can be calculated. The discussion highlights the confusion caused by the problem's wording and the need for clarity in such rotational kinematics questions.
shaka23h
Messages
38
Reaction score
0
The sun appears to move across the sky, because the Earth spins on its axis. To a person standing on the earth, the sun subtends an angle of sun = 9.30 x 10-3 rad (see Conceptual Example 2). How much time (in seconds) does it take for the sun to move a distance equal to its own diameter?



I know that I probably need convert radians to degrees and find the length of the r first?

I just don't know where the heck the time factor comes in this rotational kinematics problem. There seems to not be enough information.
 
Physics news on Phys.org
shaka23h said:
The sun appears to move across the sky, because the Earth spins on its axis. To a person standing on the earth, the sun subtends an angle of sun = 9.30 x 10-3 rad (see Conceptual Example 2). How much time (in seconds) does it take for the sun to move a distance equal to its own diameter?



I know that I probably need convert radians to degrees and find the length of the r first?

I just don't know where the heck the time factor comes in this rotational kinematics problem. There seems to not be enough information.
What is the angular speed of the observer on the earth?

AM
 
Yes, problems like these can make your head hurt.

Think of it like this: Imagine a laser beam shining from the surface of the Earth into the sky. Due to the rotation of the Earth this beam will sweep over the sky. How many radians does the beam cover in one second due to the rotation of the earth?
 
The Sun "goes around the Earth" every 1 day, that is, it rotates 2 \pi radians per day.

Convert this to 'radians per second'. Now you have a speed (in radians/second) and a distance (in radians). You can now find the time.
 
Thank god someone answered this. I've been stuck on the exact same problem from the same text. The question is worded quite poorly.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top