How long will it take for polonium-218 to decay to 30%?

  • Thread starter Thread starter Edgar92
  • Start date Start date
  • Tags Tags
    Exponent Variable
AI Thread Summary
Polonium-218 decays according to the formula A(t) = 100(0.5)^(t/3.1), and the goal is to determine the time it takes for the substance to decay to 30%. The equation simplifies to 0.3 = 100(0.5)^(t/3.1), leading to the transformation 0.3/100 = (0.5)^(t/3.1). Participants emphasize the importance of applying logarithmic laws to solve for t, noting that the exponent is divided by 3.1. The discussion highlights the need to manipulate the equation correctly to derive a linear equation in t for a solution.
Edgar92
Messages
24
Reaction score
0
1. The problem statement, all variables
a sample polonium-218 decays at A(t)=100(.5)^t/3.1
determine how many minutes it will take to decay to 30%

2. Homework Equations
log(a)/log(b)


3. The Attempt at a Solution

.3=100(.5)^t/3.1
.3/100=.5^t/3.1
 
Physics news on Phys.org
I realize this is simple but I am forgetting and don't have my textbook
 
You've already done this:

0.3=\frac{100(0.5)^t}{3.1}

\frac{0.3}{100}=\frac{(0.5)^t}{3.1}

So why don't you follow the same kind of procedure and multiply by 3.1 :smile:

and remember the log laws that if a^x=b then log_ab=x

and finally... (which you tried to show in the relevant equations but the equation was surprisingly cut short) ... log_cb=\frac{log_ab}{log_ac}
 
The exponent is divided by 3.1, not the equation
 
In that case, just use the log-exp switchy thingy immediately.
 
Edgar92 said:
The exponent is divided by 3.1, not the equation

Fine. But you can still take the log of both sides and get a linear equation in t, can't you?
 
Edgar92 said:
The exponent is divided by 3.1, not the equation

The log laws still apply.
 
Back
Top