How Many Electrons Transfer to Equalize Charge Between a Plate and a Rod?

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To equalize the charge between a plate with -3.0 microC and a rod with +2.0 microC, a total charge transfer of 5.0 microC is needed. This transfer corresponds to a movement of electrons calculated using the charge of a single electron, approximately 1.6 x 10^-19 C. The calculation shows that 3.125 x 10^13 electrons must be transferred to achieve equal charge. Participants in the discussion express confusion over unit conversions and calculations, emphasizing the importance of correctly applying the microC to C conversion. The final consensus is that 1.6 x 10^13 electrons are required for charge equalization.
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A plate carries a charge or -3.0 microC) while a rod carres a charge of +2.0 microCs. How many electrons must be transferred from the plate to the rod so that both obejcts have the same charge?


e = 1.6 X 10^-19 C. 6.25 X 10^18 e per C of negative energy..


What I've done is -3.0 mC/6.25 X 10^18= -4.8 X 10^11. 2.0 mC/ 6.25 X 10^18= 3.2 X 10^11. Added up is 1.6 X 10^11

The solution is 1.6 X 10^13 however I keep getting 1.6 X 10^11. Can someone help me out with this? What am I doing wrong? Thanks!
 
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I get 1.6 X 10^-13 electrons. Check your units. Remember that:

1\mu C=10^{-6}C
 
Would you be able to show me how you worked that because now I am getting -1.6 X 10^-25. I'm completely confused. Thanks.
 
Ok, well let me ask you this:

How much charge moves from one to the other so they have equal charge?

Once you know this, how did you convert the charge measurements to number of electrons?
 

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