How many elementary charges does this particle carry?

[Kylah]

1. A force of 9.2x10^-14 acts on an unknown particle that travels at 2.40x10⁶ m/s into a magnetic field of 4.8x10^-2 T. How many elementary charges does this particle carry?
I've used F_m=qvB and found q=F_m/vB and got an answer of q=7.986 x10^-19 C. I'm not sure where to go from here. I assume I have to divide by the elementary charge... but I don't know what that is. Haha.


2. An alpha particle with a charge of 3.20x10^-19 C and a mass of 6.65 x10^-27 kg is traveling at 5.0 x10⁶ m/s. When it enters a magnetic field of 6.4 x10^-2 T, a magnetic force provides the centripetal force for the alpha particle. The centripetal force causes the alpha particle to travel in a circular path. Calculate the radius of the circular path.
Do I simply use the equation r=(mv)/(qB)?

 

[Hootenanny]

1. A force of 9.2x10^{-14 acts on an unknown particle that travels at 2.40x106 m/s into a magnetic field of 4.8x10-2 T. How many elementary charges does this particle carry?
I've used F_m=qvB and found q=F_m/vB and got an answer of q=7.986 x10-19 C. I'm not sure where to go from here. I assume I have to divide by the elementary charge... but I don't know what that is. Haha.}

The elementary charge is the same as the magnitude of the charge of an electron, about 1.602×10^-19 C.

2. An alpha particle with a charge of 3.20x10^{-19 C and a mass of 6.65 x10-27 kg is traveling at 5.0 x106 m/s. When it enters a magnetic field of 6.4 x10-2 T, a magnetic force provides the centripetal force for the alpha particle. The centripetal force causes the alpha particle to travel in a circular path. Calculate the radius of the circular path.
Do I simply use the equation r=(mv)/(qB)?}

^{Sounds good to me}

 

[dx]

1. the charge on an electron is -1.602 176 487 × 10–19 C

2. Yes, that's the correct formula.

 

[Kylah]

Thanks!