How many moles of gold are deposited on the electrode in 10.98 hours?

[bob12345]

Homework Statement

If 3.32 kg of gold is deposited on the negative electrode of an electrolytic cell in a period of 10.98 h, what is the current in the cell in this period?Assume that each gold ion car ries one elementary unit of positive charge.

Homework Equations

i don't know what equation to use all i know is current= charge/time

The Attempt at a Solution

i couldn't find the solution because i didnt know how to use the mass??

 

[ehild]

Are you sure that it was 3.32 kg ? A big piece of gold.

Anyway: Find the molar mass of gold (about 197 g/mol) . Get the moles of gold from the given mass. Multiply by Avogadro number: you get the number of gold atoms. Each carries an elementary charge -how much is it? You know the charge and time, easy to get the current.

ehild

 

[bob12345]

yes it was 3.32 and now ill try working it out how you said

 

[bob12345]

the atomic mass is 196.97 bt how do you get it to moles?

 

[ehild]

This value means that the mass of one mole gold is 196.97 g.
If 196.97 g is one mole, how many moles are in 3.32 kg?

ehild