How Many Moles of NO2 and SO2 Are in the Mixture?

AI Thread Summary
A sample containing NO2 and SO2 has a total pressure of 120 torr, with a partial pressure of NO2 at 43 torr. The ideal gas law (PV = nRT) is used to calculate the number of moles for each gas. An initial calculation yielded 3.1 x 10^-3 moles for NO2, but the correct answer is 1.9 x 10^-3 moles. The discrepancy was due to an error in manipulating the equations, which was resolved with assistance from the forum. The discussion emphasizes the importance of careful calculations and unit management in gas law problems.
RedemistiDeus
Messages
2
Reaction score
0

Homework Statement


A sample containing only NO2 and SO2 has a total pressure of 120 torr. Measurements show that the partial pressure of NO2 is 43 torr. If the vessel has a volume of 800.0 ml and the temperature is 22.0°C, how many moles of each gas are present?

Homework Equations



PV = nRT

The Attempt at a Solution


I tried to solve it using the equation above by solving for n for each gas (using their given pressure).
For the n of NO2, I had the answer 3.1 x 10-3 (using n = PV/RT).
But the book provides a different answer for it which is 1.9 x 10-3.

My question is I would like to know how my answer turned to be incorrect. I don't know any other possible methods of solving this than the ideal gas law.
Thank you.
 
Physics news on Phys.org
I suspect you have either an arithmetic mistake and/or a mistake in units.

Please post the details of your calculations.
 
Book answer is correct.
 
Okay guys, I got it. I had an error in manipulating the equations. Thank you PF for helping me resolve the problem!
 
RedemistiDeus said:
Okay guys, I got it. I had an error in manipulating the equations. Thank you PF for helping me resolve the problem!

I'm curious as to how you arrived at the correct answer. Could you show your work?
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top