• Support PF! Buy your school textbooks, materials and every day products via PF Here!

How much work is done in moving a mole of electrons around a circuit

  • Thread starter hyperdrive
  • Start date
i know this is basic suff, but forget it, can u plz tell me how to do this question



how much work is done in moving a mole of electrons around a circut using a 6v voltage( 1 mole of electrons is 6.023 x 10 power 23 electrons


thanks

answer is w = qv = 5.78 x 10power5j
 
551
1
Do you know the charge on an electron? To find the total charge, q, multiply the charge of one electron by the number of electrons...
 
yes the charge of an eleectron is -1.6 x10power-19

sorry dont understand,

v =w/q

w=vq

v is potential difference in volts
w is work done by field in joules
q is charge being ppushed in coulombs


so w= 6 x q( which i thought was the mole of electrons, which is 6.023 x 10power23 right?)
 
551
1
If you know q is charge, as measured in coulombs, why would you think it was 6.022 x 10^23, which is the number of electrons?

If you had one electron, the work done would be, W = QV = (1.6 x 10^-19)*6..
 
k, got confused there, i hate this topic, i like the space one!

i see now:) so


w = 6* ( 1.6 x 10^-19 x number of electrons (6.023 x 10^23)
 
551
1
Yes, that's correct :smile:.
 
thanks, i have been lazey thesee holidays:P

seen these forums once before and when i formated my computer i lost the address, just found it again, i quess this is British forum(the mother land!)
 

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top