# How much work is done in moving a mole of electrons around a circuit

hyperdrive
i know this is basic suff, but forget it, can u plz tell me how to do this question

how much work is done in moving a mole of electrons around a circut using a 6v voltage( 1 mole of electrons is 6.023 x 10 power 23 electrons

thanks

answer is w = qv = 5.78 x 10power5j

## Answers and Replies

Nylex
Do you know the charge on an electron? To find the total charge, q, multiply the charge of one electron by the number of electrons...

hyperdrive
yes the charge of an eleectron is -1.6 x10power-19

sorry dont understand,

v =w/q

w=vq

v is potential difference in volts
w is work done by field in joules
q is charge being ppushed in coulombs

so w= 6 x q( which i thought was the mole of electrons, which is 6.023 x 10power23 right?)

Nylex
If you know q is charge, as measured in coulombs, why would you think it was 6.022 x 10^23, which is the number of electrons?

If you had one electron, the work done would be, W = QV = (1.6 x 10^-19)*6..

hyperdrive
k, got confused there, i hate this topic, i like the space one!

i see now:) so

w = 6* ( 1.6 x 10^-19 x number of electrons (6.023 x 10^23)

Nylex
Yes, that's correct .

hyperdrive
thanks, i have been lazey thesee holidays:P

seen these forums once before and when i formated my computer i lost the address, just found it again, i quess this is British forum(the mother land!)