How much work is done in moving a mole of electrons around a circuit

  • Thread starter hyperdrive
  • Start date
  • #1
i know this is basic suff, but forget it, can u plz tell me how to do this question



how much work is done in moving a mole of electrons around a circut using a 6v voltage( 1 mole of electrons is 6.023 x 10 power 23 electrons


thanks

answer is w = qv = 5.78 x 10power5j
 

Answers and Replies

  • #2
551
1
Do you know the charge on an electron? To find the total charge, q, multiply the charge of one electron by the number of electrons...
 
  • #3
yes the charge of an eleectron is -1.6 x10power-19

sorry dont understand,

v =w/q

w=vq

v is potential difference in volts
w is work done by field in joules
q is charge being ppushed in coulombs


so w= 6 x q( which i thought was the mole of electrons, which is 6.023 x 10power23 right?)
 
  • #4
551
1
If you know q is charge, as measured in coulombs, why would you think it was 6.022 x 10^23, which is the number of electrons?

If you had one electron, the work done would be, W = QV = (1.6 x 10^-19)*6..
 
  • #5
k, got confused there, i hate this topic, i like the space one!

i see now:) so


w = 6* ( 1.6 x 10^-19 x number of electrons (6.023 x 10^23)
 
  • #6
551
1
Yes, that's correct :smile:.
 
  • #7
thanks, i have been lazey thesee holidays:P

seen these forums once before and when i formated my computer i lost the address, just found it again, i quess this is British forum(the mother land!)
 

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