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How much work is done in moving a mole of electrons around a circuit

  • Thread starter hyperdrive
  • Start date
i know this is basic suff, but forget it, can u plz tell me how to do this question

how much work is done in moving a mole of electrons around a circut using a 6v voltage( 1 mole of electrons is 6.023 x 10 power 23 electrons


answer is w = qv = 5.78 x 10power5j
Do you know the charge on an electron? To find the total charge, q, multiply the charge of one electron by the number of electrons...
yes the charge of an eleectron is -1.6 x10power-19

sorry dont understand,

v =w/q


v is potential difference in volts
w is work done by field in joules
q is charge being ppushed in coulombs

so w= 6 x q( which i thought was the mole of electrons, which is 6.023 x 10power23 right?)
If you know q is charge, as measured in coulombs, why would you think it was 6.022 x 10^23, which is the number of electrons?

If you had one electron, the work done would be, W = QV = (1.6 x 10^-19)*6..
k, got confused there, i hate this topic, i like the space one!

i see now:) so

w = 6* ( 1.6 x 10^-19 x number of electrons (6.023 x 10^23)
Yes, that's correct :smile:.
thanks, i have been lazey thesee holidays:P

seen these forums once before and when i formated my computer i lost the address, just found it again, i quess this is British forum(the mother land!)

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