How Strong is the Attraction Between Two Humans After Electron Transfer?

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The discussion centers on calculating the attraction between two humans after transferring electrons. It involves using the formula F=kQ1Q2/r^2, where the charges Q1 and Q2 are derived from the initial number of electrons in human tissue and the transferred electrons. A key point raised is the importance of recognizing that human tissue has a balanced number of protons, resulting in a net charge of zero before the transfer. After correcting the calculations based on the net charge post-transfer, participants found more reasonable results. The conversation highlights the significance of accurately accounting for initial charges in such calculations.
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Human tissue contains about 3*10^27 electrons per kg of material. Suppose two humans are located 1370 km apart and each has a mass of 60 kg. We now transfer 5*10^21 electrons from one person to the other. What will be the magnitude of the resulting attraction, rounded to the nearest Newton?

I used the equation F=kQ1Q2/r^2

except I am not sure if I used the right charges.
for Q1, i found it by ((3*10^27)(6)-(5*10^21))(1.6*10^-19)
and Q2: ((3*10^27)(6)+(5*10^21))(1.6*10^-19)
 
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chukie said:
Human tissue contains about 3*10^27 electrons per kg of material. Suppose two humans are located 1370 km apart and each has a mass of 60 kg. We now transfer 5*10^21 electrons from one person to the other. What will be the magnitude of the resulting attraction, rounded to the nearest Newton?

I used the equation F=kQ1Q2/r^2

except I am not sure if I used the right charges.
for Q1, i found it by ((3*10^27)(6)-(5*10^21))(1.6*10^-19)
and Q2: ((3*10^27)(6)+(5*10^21))(1.6*10^-19)
Why are you using 3 x 10^27? Those electrons are balanced by an equal number of protons so there is 0 net charge. You want to find the net charge after the transfer of 5 x 10^21 electrons.

AM
 
oh okay, thanks! the answer i got now is more reasonable =)
 
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