How to calculate change in pressure from LN2 phase change

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To calculate the increase in pressure caused by liquid nitrogen (LN2) transitioning to vapor in a closed, constant volume at atmospheric pressure, one must consider the vapor pressure of LN2, which accurately represents the pressure exerted by the gas on the container walls. The heat of vaporization is relevant as heat is added to evaporate the liquid, causing the pressure to rise. Starting with one mole of LN2 at its boiling temperature and atmospheric pressure, the process involves heating until all liquid evaporates, which increases both pressure and boiling temperature. The vapor pressure can be determined using tables that correlate temperature and pressure for nitrogen gas, ensuring to account for the molar volume of the vapor. If the tables do not provide sufficient data, the critical temperature and pressure can be used to find the appropriate values for supercritical conditions.
AndyPivot
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I am trying to calculate the increase in pressure caused by liquid nitrogen when it changes from liquid to vapor within a closed, constant volume at atmospheric pressure. How can this be done? Do I need to include the heat of vaporization?
 
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So, the vapor pressure is an accurate representation of the pressure exerted by the LN2 gas on the walls of any closed container?
 
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AndyPivot said:
increase in pressure...at atmospheric pressure. How can this be done?
Zero is identically "zρ." Now, what is your question? Did you want vapor pressure as a function of temperature?
 
Let's say you start with a mol of LN2 at one atmosphere at its boiling temperature, and you fix a cap on it (constant volume). You can look up the volume it displaces and the temperature on your own...

Add heat until it's all evaporated. As it evaporates, pressure rises, and boiling temperature rises. You know you have a molar volume of vapor (starting with one mol N2), so look up the temperature/pressure of N2 gas with that molar volume in equilibrium with liquid. If you run out of table before you get to that volume, then you can probably stop at the critical temperature, and find the (supercritical) pressure that provides the correct molar volume.
 
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