How to Calculate Flux Density at a Point Using a 3-A Current?

AI Thread Summary
To calculate the flux density at a point using a 3-A current, the formula B = I x 10^-7 ∫(sinΘ/r²)dl is applied. The user attempts to solve it with specific values but expresses confusion about the process and the relevance of examples found in other resources. They seek clarification on the steps involved in solving their particular problem. The discussion highlights a need for more tailored guidance in understanding the calculation of flux density. Assistance is requested to navigate the complexities of the problem.
LandonV
Messages
9
Reaction score
0

Homework Statement



Someone else posted up this image on yahoo answers and my question is very similar except the numerical figures are different really.

http://s3.supload.com/free/Picture_258.jpg/view"

How can i solve for for the flux density at the point using the 3-A current?

Homework Equations



B = I x 10^-7 \intlbla (sin\Theta/r2)dl

The Attempt at a Solution



B=3 x 10^-7/.02m \intlbla (sin 90/2.52).07m

I am no even sure if I am attempting this correctly. Everything I'm reading doesn't really explain the steps to get the answer. They give other examples that look nothing like my problem so I am lost as can be. Can someone help me out here?
 
Last edited by a moderator:
Physics news on Phys.org
can no one help me out?
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top