How to Calculate Partial Pressure of NOCl in a Chemical Reaction?

AI Thread Summary
To calculate the partial pressure of NOCl in the reaction 2NO (g) + Cl2 (g) ⇌ 2NOCl (g) with a given Kp of 6.5×10^4, the equation Kp = (P_NOCl)^2 / (P_NO)^2 * (P_Cl2) is used. Given the partial pressures P_NO = 0.35 atm and P_Cl2 = 0.10 atm, the calculation for P_NOCl involves substituting these values into the equation. The proposed solution is P_NOCl = √[(6.5×10^4) * (0.35)^2 * (0.10)]. The approach taken in the calculation is confirmed to be correct.
aaronfue
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Homework Statement



I am given the following equation:

2NO (g) + Cl2 (g) \rightleftharpoons 2NOCl (g)

Kp = 6.5×104
PNO = 0.35 atm
PCl2 = 0.10 atm

I need to calculate PNOCl.

Homework Equations



Kp = \frac{(P_{NOCl})^2}{(P_{NO})^2*(P_{Cl_2})}

The Attempt at a Solution



I was given Kp = 6.5×104

After plugging in my partial pressures for NO and Cl2 I got:

PNOCl = \sqrt{(6.5×10^4)*(0.35)^2*(0.10)}

Is this the correct way to calculate this?

Thanks!
 
Last edited:
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That looks good to me!
 
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