How to Determine Electric Flow Through a Square Surface Due to a Nearby Charge?

AI Thread Summary
To determine the electric flow through a square surface due to a nearby charge, the problem involves calculating the electric field from a charge +Q located at a distance l from the center of the square. A double integral was initially considered for the calculation, but participants suggest leveraging symmetry to simplify the process. Applying Gauss's law is recommended, with the suggestion to divide the result by 1/6 due to the symmetry of the configuration. Clarification is sought on the closed surface for Gauss's law, with a cube being a potential option. The discussion emphasizes that using symmetry and Gauss's law can streamline the solution significantly.
Est120
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Homework Statement


determine the electric flow through a square surface of side 2l due to a load + Q located at a perpendicular distance l from the center of the plane

I really don't know how to answer this question .i need help guys
Thanks

Homework Equations

The Attempt at a Solution


I ended up with a doble integral ,which i had to evaluate in order to calculate the flow of electric fiele in the whole square
 
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Can you share the details of the the work you've done so far? Is there a figure that accompanies the problem that you can upload?
 
upload_2018-10-6_8-0-3.png
upload_2018-10-6_8-5-50.png

this would be the image ,and i tried this:
im new to this kind of things also English is not my principal language
 

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You may not need to do an integration for this. Take advantage of the symmetry
 
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Chandra Prayaga said:
You may not need to do an integration for this. Take advantage of the symmetry
Should i just apply Gauss law And multiply by 1/6 ?
 
Est120 said:
Should i just apply Gauss law And multiply by 1/6 ?
If you can assume that the Y-axis passes through the center of the square so that symmetry is preserved, then yes.
 
The question will be, what is the closed surface on which you are applying Gauss's law, before dividing by 1/6?
 
Chandra Prayaga said:
The question will be, what is the closed surface on which you are applying Gauss's law, before dividing by 1/6?
A cube ,but i don't know if it's as easy as that
 
Est120 said:
A cube ,but i don't know if it's as easy as that
Actually, it is as easy as that! (With the assumption described in post #6).
 
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I would say, just go ahead and try it.
 
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