How to find the intersection of a cylinder and a plane?

seto6
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Homework Statement



The plane x+y+z=1 cuts the cylinder x^{2}+y^{2}=1 in an ellipse. Find the points on this ellipse that lie closests to and farthest from the origin.

Homework Equations


N/A

The Attempt at a Solution


first step was to determine the intersection of the plane and the cylinder.
so x+y+z=x^{2}+y^{2}, but i am kinda stuck solving this
i got to this far but i am really stuck, (x-3)(x+2)+6+(y-3)(y+2)+6=z.
any hints will really be appriciated, since this is one of the past exam questions. if i can find the intersection i can go on from there.
 
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do you know lagrange multipliers?

just minimise distance to origin, or similarly x^2 + y^2 + z^2, with the constraints being the plane and the cylinder
 
thank you very much Lanedance,
i can not believe that i did not think of Lagrange multipliers.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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