How to find the mass of a compound given the half life and activity?

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SUMMARY

The discussion focuses on calculating the mass of sodium sulfate (Na2SO4) with a specified activity of 10.0 mCi, utilizing the half-life of sulfur-38, which is 2.87 hours. The relevant equations include the half-life formula, expressed as half life = 0.693/k, and the rate equation, rate = kN. Participants express confusion regarding the interpretation of the activity measurement and the application of the half-life in the context of the problem.

PREREQUISITES
  • Understanding of radioactive decay concepts
  • Familiarity with the half-life equation
  • Knowledge of activity measurement in millicuries (mCi)
  • Basic skills in stoichiometry and mass calculations
NEXT STEPS
  • Study the relationship between activity and the number of radioactive nuclei
  • Learn how to convert activity in mCi to decay constant (k)
  • Explore stoichiometric calculations involving compounds like Na2SO4
  • Review examples of radioactive decay problems involving half-life
USEFUL FOR

Students in chemistry or physics courses, educators teaching radioactive decay, and anyone needing to solve problems involving half-life and activity in nuclear chemistry.

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Homework Statement


What mass of Na2 SO4 has an activity of 10.0 mCi? Sulfur-38 has an atomic mass of 38.0 and a half life of 2.87h


Homework Equations



Half life= 0.693/ k

Rate= kN

The Attempt at a Solution


I'm not sure where to begin the sulfur-38 part is throwing me off
All I need is some hint as to where to begin
 
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What 10 mCi means?

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