How to Find the Reading of Voltmeters in a Circuit with Identical Resistors?

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Homework Help Overview

The discussion revolves around a circuit problem involving identical resistors and ideal voltmeters. Participants are tasked with determining the readings of the voltmeters based on the given voltage and resistance values.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the application of Kirchhoff's Law and the calculation of current in the circuit. There are attempts to clarify the relationships between voltages and currents in different loops of the circuit.

Discussion Status

There is an ongoing examination of the calculations related to current and voltage readings. Some participants have offered corrections to earlier calculations, while others question the validity of the proposed answers, indicating a lack of consensus on the correct readings of the voltmeters.

Contextual Notes

Participants are navigating through potential misinterpretations of the circuit setup and the implications of using ideal voltmeters. There is a focus on ensuring that the problem is stated correctly to arrive at accurate conclusions.

utkarshakash
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Homework Statement


In the circuit shown below, all three voltmeters are ideal and identical. Each resistor has the same given resistance R. Voltage V is also given. Find the reading of each voltmeter.


The Attempt at a Solution



i = 2V/3R
Applying Kirchhoff's Law to BACDE
V1+V2=0

Loop CDHFG
V1+V3=2V/3

Loop DEH
V2+V3=2V/3

Solving these three, I get incorrect answers.
 

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You've calculated I incorrectly. Since the voltage V appears across 3 R's in series, I = V/(3R).
 
phyzguy said:
You've calculated I incorrectly. Since the voltage V appears across 3 R's in series, I = V/(3R).

Oops! I used incorrect notation for current. The current in the circuit as a whole is 2V/3R. The currrents in individual branches are V/3R.
 
utkarshakash said:
Oops! I used incorrect notation for current. The current in the circuit as a whole is 2V/3R. The currrents in individual branches are V/3R.

Correct. Does this solve your original problem?
 
phyzguy said:
Correct. Does this solve your original problem?

No. The correct answers are V1=V2=V/9 and V3=2V/9
 
utkarshakash said:
No. The correct answers are V1=V2=V/9 and V3=2V/9

If you've posted the problem correctly, I don't think that can be the correct answer. VC = VE = V/3, so V1 and V2 should both read 0 and V3 should read V/3.
 

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