Hurling protons at one another to find where they stop

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When two protons with an initial kinetic energy of 0.19 MeV are hurled towards each other, they will momentarily stop when their kinetic energy is fully converted into electric potential energy. The relevant formula for electric potential energy is k(q1*q2)/r, where k is the Coulomb's constant and r is the separation distance. At the point of stopping, the separation distance between the protons is calculated to be 1 meter. This demonstrates the relationship between kinetic energy and electric potential energy in particle interactions. Understanding this conversion is crucial for analyzing proton collisions in physics.
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Two protons that are very far apart are hurled straight at each other, each with an initial kinetic energy of 0.19 MeV, where 1 mega electron volt is equal to (1*10^6)*(1.6*10^-19) joules. What is the separation of the protons from each other when they momentarily come to a stop?
separation = 1 m

Maybe I'm just missing the necessary formula. Is there a way to incorporate Electric Potential Energy formula and the energy principle here?
 
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HellaciousD said:
Two protons that are very far apart are hurled straight at each other, each with an initial kinetic energy of 0.19 MeV, where 1 mega electron volt is equal to (1*10^6)*(1.6*10^-19) joules. What is the separation of the protons from each other when they momentarily come to a stop?
separation = 1 m

Maybe I'm just missing the necessary formula. Is there a way to incorporate Electric Potential Energy formula and the energy principle here?

Certainly. The protons will stop when all their kinetic energy is converted to electric potential energy.
Both of the protons have kinetic energy at the start. The potential energy \frac {k q_1 q_2} {r} is shared by both protons.
 
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