Robert Mak
- 26
- 0
Integral of ((Tan x)^6)dx
i think that the solution is:
(1/5)(tan x)^5 + (1/3)(tan x)^3 - (2/3)(tan x)^3 + tan x - x + c
but if i derivate this solution it lead me to that:
(tan x)^4((tan x)^2 + 2)
?
i think that the solution is:
(1/5)(tan x)^5 + (1/3)(tan x)^3 - (2/3)(tan x)^3 + tan x - x + c
but if i derivate this solution it lead me to that:
(tan x)^4((tan x)^2 + 2)
?
