# Ideal gas expansion

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1. May 28, 2016

### Tardis Traveller

1. The problem statement, all variables and given/known data
A bubble comes from the bottom of the tank of water to the surface and triples in its volume. If the temperature of the tank of water doesnt deppend on the depth what is the depth of the tank that the bubble was at?

2. Relevant equations
$PV=nRT$

3. The attempt at a solution
Since the temperature stays constant i guessed
$P_bV_b=P_uV_u$
$P_bV_b=P_u3V_b$
and i get 30m but the answer states 20m. What is wrong?

2. May 28, 2016

### SteamKing

Staff Emeritus
What's the pressure at the surface of the water?

3. May 29, 2016

### Tardis Traveller

The atmospheric pressure 1000 kg/m3

4. May 29, 2016

### SteamKing

Staff Emeritus
That's not right; it's not even wrong.

Pressure has units of force per unit area. 1000 kg/m3 is the density of fresh water (approximately).

You should look up what the value of a standard atmosphere is.

5. May 30, 2016

### Tardis Traveller

Oops, your absolutely right i gave you the density, its 100kPa actually at the surface

6. May 30, 2016

### SteamKing

Staff Emeritus

Since the top of the tank is presumably open to the atmosphere, the pressure at the water's surface will be atmospheric.

What's the pressure acting on the bubble when it is submerged and starts to rise?

7. May 30, 2016

### ogg

P1V1=P2V2 is correct, of course. In order for V2 = 3*V1 it must be P2 = P1÷3
So, you know at depth X, P is 3 times atmospheric. Since you haven't shown any further work about how pressure increases with water depth, I'll stop here.