Ideal Gas Expansion: Finding Depth of Tank

In summary, the pressure at the surface of the water is 1000 kg/m3, and the pressure at the surface of the water is 2000 kg/m3.
  • #1
Tardis Traveller
5
0

Homework Statement


A bubble comes from the bottom of the tank of water to the surface and triples in its volume. If the temperature of the tank of water doesn't deppend on the depth what is the depth of the tank that the bubble was at?

Homework Equations


##PV=nRT##

The Attempt at a Solution


Since the temperature stays constant i guessed
##P_bV_b=P_uV_u##
##P_bV_b=P_u3V_b##
and i get 30m but the answer states 20m. What is wrong?
 
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  • #2
What's the pressure at the surface of the water?
 
  • #3
SteamKing said:
What's the pressure at the surface of the water?
The atmospheric pressure 1000 kg/m3
 
  • #4
Tardis Traveller said:
The atmospheric pressure 1000 kg/m3
That's not right; it's not even wrong.

Pressure has units of force per unit area. 1000 kg/m3 is the density of fresh water (approximately).

You should look up what the value of a standard atmosphere is.
 
  • #5
SteamKing said:
That's not right; it's not even wrong.

Pressure has units of force per unit area. 1000 kg/m3 is the density of fresh water (approximately).

You should look up what the value of a standard atmosphere is.
Oops, your absolutely right i gave you the density, its 100kPa actually at the surface
 
  • #6
Tardis Traveller said:
Oops, your absolutely right i gave you the density, its 100kPa actually at the surface
You should draw a sketch to help you focus.

Since the top of the tank is presumably open to the atmosphere, the pressure at the water's surface will be atmospheric.

What's the pressure acting on the bubble when it is submerged and starts to rise?
 
  • #7
P1V1=P2V2 is correct, of course. In order for V2 = 3*V1 it must be P2 = P1÷3
So, you know at depth X, P is 3 times atmospheric. Since you haven't shown any further work about how pressure increases with water depth, I'll stop here.
 

1. What is an ideal gas expansion?

An ideal gas expansion is the process in which a gas expands without any change in temperature or pressure. It is governed by the ideal gas law, which states that the product of the pressure and volume of an ideal gas is directly proportional to its temperature.

2. How is the depth of a tank determined using ideal gas expansion?

The depth of a tank can be determined by measuring the change in volume of a gas as it expands from a confined space (such as a tank) to a larger volume. This change in volume can be used to calculate the pressure and temperature of the gas, which can then be used to determine the depth of the tank using the ideal gas law.

3. What factors affect the accuracy of using ideal gas expansion to find the depth of a tank?

The accuracy of using ideal gas expansion to find the depth of a tank can be affected by several factors, including the accuracy of the pressure and volume measurements, the presence of impurities in the gas, and any changes in the temperature or pressure during the expansion process.

4. Can any gas be used for ideal gas expansion to find the depth of a tank?

No, only gases that behave as an ideal gas can be used for this method. This means that the gas must follow the ideal gas law at the given temperature and pressure conditions.

5. What are some practical applications of using ideal gas expansion to find the depth of a tank?

This method can be used in various industries, such as oil and gas, to measure the depth of tanks or containers. It can also be used in scuba diving to calculate the depth of a dive based on changes in air volume and pressure. Additionally, it can be used in laboratory experiments to study the behavior of gases.

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