Ideal Gas Law and kinetic energy

AI Thread Summary
To calculate the kinetic energy of gas molecules in a 45 m³ room at 30°C, the ideal gas law (PV = nRT) is essential. The pressure is assumed to be 1 atm, and the relationship KE = (3/2)kT can be used to find the kinetic energy per particle, where k is Boltzmann's constant. By converting the temperature to Kelvin and determining the number of moles of air in the room, one can compute the total kinetic energy. The calculations involve using the volume of air per mole at standard conditions to find the total moles in the room. This approach leads to an accurate determination of the total kinetic energy of the gas molecules.
snoopygal327
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Homework Statement


An empty room in a house near the Atlantic coast has a volume of 45m3. What is the kinetic energy of all of the gas molecules in the room on a 30C summer day?

Homework Equations


pv = nrt

The Attempt at a Solution


I realize that this is an ideal gas law problem, but I have no idea where to start. How can I solve for anything if I'm only given volume and temperature?
 
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snoopygal327 said:

Homework Statement


An empty room in a house near the Atlantic coast has a volume of 45m3. What is the kinetic energy of all of the gas molecules in the room on a 30C summer day?

Homework Equations


pv = nrt

The Attempt at a Solution


I realize that this is an ideal gas law problem, but I have no idea where to start. How can I solve for anything if I'm only given volume and temperature?

You are on the right track. Maybe start here?
http://en.wikipedia.org/wiki/Kinetic_theory#Temperature_and_kinetic_energy
 
LowlyPion said:

Okay, so I use the equation PV = (2/3)K. I assumed that the pressure is the standard 1 atm. Plugging everything into the equation:

101300 Pa (45 m3) = (2/3)K
K = 6837750 J

But the computer is telling me that this is the wrong answer. Did I do something wrong?
 
snoopygal327 said:
Okay, so I use the equation PV = (2/3)K. I assumed that the pressure is the standard 1 atm. Plugging everything into the equation:

101300 Pa (45 m3) = (2/3)K
K = 6837750 J

But the computer is telling me that this is the wrong answer. Did I do something wrong?

I think perhaps you want to use the relationship that KE = 3/2*k*T
That gives you the KE per particle and you can figure the number of particles from the Volume at 30° C = 303° K.
The k here is Boltzmann's constant 1.38 *10-23 J/°K

Noting that the volume of air occupied by 1000 moles of air is given here:
Wikipedia said:
V/n = 8.3145 × 298.15 / 101.325 = 24.466 m3/kmol at 25 °C and 101.325 kPa
http://en.wikipedia.org/wiki/Standard_conditions_for_temperature_and_pressure

With 41 (1000/24.466) moles of air per m3 *45 m3 ... then you should be able to figure the total KE for that many moles of air in a 45 m3 room.
 
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