Impedance of practical Capacitor

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Discussion Overview

The discussion revolves around calculating the impedance of a practical capacitor modeled as an ideal capacitor in parallel with a resistor at a specific radian frequency. Participants are attempting to reconcile their calculations with a provided book solution, leading to questions about their methods and potential errors.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents a formula for the impedance of a practical capacitor and attempts to calculate it using given values for capacitance and resistance.
  • Another participant requests clarification on the reasoning and working behind the calculations.
  • Multiple participants express confusion over discrepancies between their calculated angles and the book's results, specifically regarding the arctangent function.
  • One participant suggests that the book may contain an error or that they might have missed a step in their calculations.
  • Another participant confirms that their calculations align with the book's result for a different example, but they note that rounding may affect the final angle.
  • One participant identifies that they were using degree mode instead of radian mode for their calculations, which could explain the discrepancies.

Areas of Agreement / Disagreement

Participants express uncertainty regarding the accuracy of their calculations and the book's solutions. There is no consensus on the source of the discrepancies, as some participants believe their methods are correct while others suspect errors in the book or in their own calculations.

Contextual Notes

Participants mention potential issues with rounding and the use of different angle measurement modes (degrees vs. radians), which may affect the results. There is also a lack of clarity on how certain values were derived in the book's solutions.

Who May Find This Useful

This discussion may be useful for students working on similar problems involving the impedance of capacitors, particularly those grappling with the effects of complex numbers and angle calculations in electrical engineering contexts.

bigu01
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Homework Statement


A practical capacitor can be modeled by an ideal capacitor in parallel with a resistor.Find the impedance of practical capacitor at the radian frequency ω=377rad/s.Known C1=0.1 x 10^-6F R1=1 *10^6.

Homework Equations



1/Z=1/R1 + jCω

The Attempt at a Solution

I am first determining the Z, by adding the impedance of resistor and the capacitor in parallel.
And I am getting Z1(377)=10^6/(1+j37.7)= 2.6516*10^4 ∠-1.519 However book solutions gives ∠-1.5443.I would like to get some help about where my mistake is,or how should I approach the question. I know that finding the angle we should do θ=arctan(y/x) where y is the imaginary part and x is the real part.Hope I was clear and did not complicate it.
 
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Please show your reasoning and working.
 
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R//C Z=R//1/jωC = R1/(1+jωC1R1) inputing numbers I get =10^6/(1+j37.7) multiplying by 1+j37.7's conjugate I got 703.09-26506.54j , tried to find the length got the 26515.86 , finding the angle theta=arctan(-26506.54/703.09) doesn't give me same as book result. I get -1.519 book got -1.5443
 
Looking at my procedure everything looks fine.I am wondering if book has done any mistake,or there is something else I should do, which I have missed,and it is making me do the mistake.
 
bigu01 said:
R//C Z=R//1/jωC = R1/(1+jωC1R1) inputing numbers I get =10^6/(1+j37.7) multiplying by 1+j37.7's conjugate I got 703.09-26506.54j , tried to find the length got the 26515.86 , finding the angle theta=arctan(-26506.54/703.09) doesn't give me same as book result. I get -1.519 book got -1.5443

Your numbers all look fine except for the result of the arctan(). When I enter that argument and take the arctan I get the book's result.
 
gneill said:
Your numbers all look fine except for the result of the arctan(). When I enter that argument and take the arctan I get the book's result.

You're saying that arctan(26506.54/703.09) gives 1.554 , either my two calculators are wrong or I am doing something wrong.
 
bigu01 said:
You're saying that arctan(26506.54/703.09) gives 1.554 , either my two calculators are wrong or I am doing something wrong.

That's what I'm saying :smile:
 
Okay then, what about this one 101.92+j90.38,what do you get as your ∠? The book answer is ∠0.723 and about this one I have no clue how did they get it
 
bigu01 said:
Okay then, what about this one 101.92+j90.38,what do you get as your ∠? The book answer is ∠0.723 and about this one I have no clue how did they get it

The numbers are probably rounded somewhat. I get 0.725 radians as the angle.
 
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  • #10
Multiple threads are confusing... it looks like the error was here:
bigu01 said:
I was using the degree mode, I should have used the radian angle unit one

I have no idea how you get -1.519 in degree mode... well does not matter.
 

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